Submission
Status:
[PPPPPPPPPP]
Score: 100
User: jxkrpn
Problemset: บาร์โค้ด
Language: c
Time: 0.001 second
Submitted On: 2024-09-27 13:58:26
#include"stdio.h"
#include"string.h"
void Reverse(int ar[],int n){
for(int i=0;i<n/2;i++){
int temp = ar[i];
ar[i]=ar[n-i-1];
ar[n-i-1]=temp;
}
}
int main(){
int i=0,j,k,result;
char n[20];
int ar[20];
int re[20];
scanf("%s",n);
k = strlen(n);
for(i=0;i<k;i++){
ar[i]= n[i]-'0';
}
for(j=0;j<k;j++){
re[j]=ar[k-j-1];
}
if (k >= 13) {
Reverse(re, 13);
} else {
Reverse(re, k);
}
int sum=0;
for(i=0;i<k && i<13;i+=2){
sum+=re[i];
}
int sum2=0;
for(i=1;i<k && i<13;i+=2){
sum2+=re[i];
}
sum2=sum2*3;
result = sum+sum2;
if(result%10 ==0){
printf("YES");
}else{
printf("NO");
}
return 0;
}