Submission
Status:
PPPPPTPPPPPPPPPP
Score: 150
User: Nagornz
Problemset: Chocolate
Language: cpp
Time: 1.090 second
Submitted On: 2025-03-15 13:26:24
#pragma GCC optimize("Ofast,no-stack-protector,unroll-loops,fast-math,no-stack-protector,inline-small-functions,inline,unsafe-math-optimizations,omit-frame-pointer,inline-functions-called-once")
#include <iostream>
#include <vector>
#pragma GCC target("avx2,fma,popcnt,lzcnt,bmi,bmi2,sse4.2,tune=native")
#define emb emplace_back
#define iShowSpeed cin.tie(NULL)->sync_with_stdio(false)
using namespace std;
const int mod = 1e9 + 7;
const int N = 5005;
int dp[2][N];
int a[N];
vector <int> pref[N];
long long poww(int a, int n){
long long ans = 1;
while (n) {
if (n % 2) ans *= a;
a *= a;
n /= 2;
}
return ans;
}
int addmod(int a, int b) {
a += b;
if (a >= mod) a -= mod;
return a;
}
int submod(int a, int b) {
a -= b;
if (a < 0) a += mod;
return a;
}
int main(){
iShowSpeed;
int n, k, c; cin >> n >> k >> c;
for (int i = 1; i <= n; i++) cin >> a[i];
int ll, rr; cin >> ll >> rr;
for (int i = 1; i <= n; i++) {
for (int j = i; j <= n; j++) {
int num = pref[i].size() ? pref[i].back() : 0;
long long powerr = poww(j - i, c);
if (powerr > rr / abs(a[j])) break;
long long cal = num + a[j] * powerr;
if (cal > rr) break;
pref[i].emb(cal);
}
}
// cout << "---------------\n";
for (int i = 1; i <= n; i++) {
if (i - 1 >= pref[1].size()) break;
dp[1][i] = (pref[1][i - 1] >= ll && pref[1][i - 1] <= rr);
// cout << 1 << ", " << i << ": " << dp[1][i] << "\n";
}
// cout << "---------------\n";
for (int i = 2; i <= k; i++) {
int curr = i & 1, prev = curr ^ 1;
for (int j = 1; j <= n; j++) {
dp[prev][j] = addmod(dp[prev][j], dp[prev][j - 1]);
}
for (int j = 1; j <= n; j++) {
int l = 1, r = j, lidx = -1, ridx = -1;
while (l <= r) {
int mid = (l + r) >> 1;
if (j - mid + 1 > pref[mid].size()) {
l = mid + 1;
continue;
}
if (pref[mid][j - mid] <= rr) r = mid - 1, lidx = mid;
else l = mid + 1;
}
l = 1, r = j;
while (l <= r) {
int mid = (l + r) >> 1;
if (j - mid + 1 > pref[mid].size()) {
l = mid + 1;
continue;
}
if (pref[mid][j - mid] >= ll) l = mid + 1, ridx = mid;
else r = mid - 1;
}
if (ridx == -1 || lidx == -1) dp[curr][j] = 0;
else {
dp[curr][j] = submod(dp[prev][ridx - 1], (lidx == 1 ? 0 : dp[prev][lidx - 2]));
}
}
}
cout << dp[k & 1][n];
}